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NEW QUESTION: 1

A. 192.168.4.125
B. 192.168.4.132
C. 192.168.4.67
D. 192.168.4.63
E. 192.168.4.61
F. 192.168.4.128
Answer: A,C
Explanation:
Explanation
Increment: 64 (/26 = 11111111.11111111.11111111.11000000)
The IP 192.168.4.0 belongs to class C.
The default subnet mask of class C is /24 and it has been subnetted with a /26 mask so we have 2(26-24) = 22 = 4 sub-networks:
1st subnet: 192.168.4.0 (to 192.168.4.63)
2nd subnet: 192.168.4.64 (to 192.168.4.127)
3rd subnet: 192.168.4.128 (to 192.168.4.191)
4th subnet: 192.168.4.192 (to 192.168.4.225)
In all the answers above, only answer C and D are in the same subnet.
Therefore only IPs in this range can be assigned to hosts.

NEW QUESTION: 2
Given:

What is result?
A. Compilation fails
B. An exception is thrown at runtime
C. Successful
D. Unsuccessful
Answer: A

NEW QUESTION: 3
Ein Techniker erstellt einen Windows-Server, um die spezifischen Anforderungen eines Benutzers zu erfüllen. Der Benutzer muss ein Replikat einer sehr großen SQL-Datenbank unterbringen, um die Datenbank lokal abfragen zu können.
Welche der folgenden Laufwerkskonfigurationen würde BEST die Anforderungen erfüllen und gleichzeitig die maximale Leistung und Speicherkapazität bieten?
A. Betriebssystemfestplatte: 256 GB Festplatte mit 5400 U / min
Datenfestplatte: 1 TB Festplatte mit 5400 U / min
D18912E1457D5D1DDCBD40AB3BF70D5D
B. Betriebssystemfestplatte: 128 GB M2
Datenfestplatte: 4 TB Festplatte mit 7200 U / min
C. Betriebssystemfestplatte: 512 GB Festplatte mit 15000 U / min
Datenfestplatte: 64 GB M2
D. Betriebssystemfestplatte: 1 TB Festplatte mit 7200 U / min
Datenfestplatte: 128 GB Festplatte mit 10000 U / min
Answer: B