VMware 2V0-13.24 Q&A - in .pdf

  • 2V0-13.24 pdf
  • Exam Code: 2V0-13.24
  • Exam Name: VMware Cloud Foundation 5.2 Architect
  • PDF Version: V19.35
  • Q & A: 365 Questions and Answers
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NEW QUESTION: 1
An integration developer opens a process application in the IBM Integration Designer (IID) workspace. It contains a business data object CandidateData, a business process definition (BPD) CheckCandidateData and there is no integration service or toolkit dependency associated with this process application.
Which artifacts related to the process application will the integration developer see in advanced mode when the process application is imported in the IID workspace?
The CheckCandidateData BPD under:
A. Processes and a business object under Data, and no generated interfaces.
B. Processes, automatically generated interfaces under Interfaces, and a business object under Data.
C. Processes, automatically generated interfaces under Interfaces, a business object under Data, and an unimplemented integration service under Advanced Integration Services.
D. Integration Logic, automatically generates under Interfaces, and a business object under Data.
Answer: B

NEW QUESTION: 2
AWS Direct Connectについて正しい記述はどれですか?
A. AWS Direct Connectロケーションは、関連付けられているリージョンのAmazon Webサービスへのアクセスを提供します。
B. AWS Direct Connectへの接続には、ポートで自動ネゴシエーションが有効になっている1ギガビットイーサネットのダブルクラッドファイバーが必要です。
C. AWS Direct Connectを使用するには、ネットワークを新しいAWS Direct Connectロケーションと併置する必要があります。
D. AWS Direct Connectは、標準の50ギガビットイーサネットケーブルを介して内部ネットワークをAWS Direct Connectロケーションにリンクします。
Answer: A
Explanation:
説明
AWS Direct Connectは、標準の1ギガビットまたは10ギガビットイーサネット光ファイバーケーブルを介して、内部ネットワークをAWS Direct Connectロケーションにリンクします。 AWS Direct Connectロケーションは、関連付けられているリージョンのAmazon Webサービスへのアクセスと、他の米国リージョンへのアクセスを提供します。 AWS Direct Connectを使用するには、ネットワークを既存のAWS Direct Connectロケーションと併置します。 AWS Direct Connectへの接続には、シングルモードファイバー、1ギガビットイーサネットの場合は1000BASE-LX(1310nm)、10ギガビットイーサネットの場合は10GBASE-LR(1310nm)が必要です。ポートの自動ネゴシエーションを無効にする必要があります。
http://docs.aws.amazon.com/directconnect/latest/UserGuide/Welcome.html

NEW QUESTION: 3
Given:
import java.util.*;
public class StringApp {
public static void main (String [] args) {
Set <String> set = new TreeSet <> ();
set.add("X");
set.add("Y");
set.add("X");
set.add("Y");
set.add("X");
Iterator <String> it = set.iterator ();
int count = 0;
while (it.hasNext()) {
switch (it.next()){
case "X":
System.out.print("X ");
break;
case "Y":
System.out.print("Y ");
break;
}
count++;
}
System.out.println ("\ncount = " + count);
}
}
What is the result?
A. X X Y X Y count = 5
B. X Y X Y count = 4
C. X Y count = 2
D. X Y count = s
Answer: C
Explanation:
A set is a collection that contains no duplicate elements. So set will include only two
elements at the start of while loop. The while loop will execute once for each element. Each
element will be printed.
Note:
*public interface Iterator
An iterator over a collection. Iterator takes the place of Enumeration in the Java collections
framework. Iterators differ from enumerations in two ways:
Iterators allow the caller to remove elements from the underlying collection during the iteration with
well-defined semantics.
Method names have been improved.
*hasNext
public boolean hasNext()
Returns true if the iteration has more elements. (In other words, returns true if next would return an
element rather than throwing an exception.)
*next
publicObjectnext()
Returns the next element in the iteration.

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