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NEW QUESTION: 1



A. Switch B - Fa0/0
B. Switch C - Fa0/0
C. Switch C - Fa0/1
D. Switch A - Fa0/0
E. Switch B - Fa0/1
F. Switch A - Fa0/1
Answer: A,E,F
Explanation:
This question is to check the spanning tree election problem.
1.First, select the root bridge, which can be accomplished by comparing the bridge ID, the smallest will be selected. Bridge-id= bridge priority + MAC address. The three switches in the figure all have the default priority, so we should compare the MAC address, it is easy to find that SwitchB is the root bridge.
2.Select the root port on the non-root bridge, which can be completed through comparing root path cost. The smallest will be selected as the root port.
3.Next, select the Designated Port. First, compare the path cost, if the costs happen to be the same, then compare the BID, still the smallest will be selected. Each link has a DP. Based on the exhibit above, we can find DP on each link. The DP on the link between SwitchA and SwitchC is SwitchA'Fa0/1, because it has the smallest MAC address.

NEW QUESTION: 2
展示を参照してください。

ホスト10.0.1.5宛てのトラフィックのネクストホップアドレスは何ですか。
A. Loopback D
B. 10.0.1.3
C. 10.0.1.4
D. 10.0.1.50
Answer: D

NEW QUESTION: 3
You are developing a web page that consumes a Windows Communication Foundation (WCF) service. The page includes the following code segment.
var xhr = new XMLHttpRequest() ;
The page uses the xhrHandler() method to listen for changes to the request status of the WCF service calls. It uses the xmlToJavaScript() method to convert the response from the WCF service to a JavaScript object.
The xhrHandler() method must be called automatically each time the request status
changes.
You need to add the event handler to the request object.
Which line of code should you use?
A. xhr.status = xhrHandler;
B. xhr.onCallback = xhrHandler;
C. xhr.readyState = xhrHandler;
D. xhr.onreadystatechange = xhrHandler;
Answer: D
Explanation:
Reference:
http://mrfwebdesign.blogspot.ca/2008/11/xmlhttprequest-xhr.html