VMware 3V0-42.23 Q&A - in .pdf

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  • Exam Name: VMware NSX 4.x Advanced Design
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NEW QUESTION: 1
Which graph structure would best model the relationship between job seekers and employers?
A. Bipartite
B. Ranked
C. Directed acyclic
D. Weighted
Answer: A

NEW QUESTION: 2
Select correct choice?
A. Using edge locations to put content closer to all users
B. Using a second Availability Zone in the AWS Region that is using used
C. Enabling caching in the AWS Region that is being used
D. Using an AWS Region that is central to all users
Answer: D

NEW QUESTION: 3
-- Exhibit --
[edit routing-options]
user@R1# show
static {
route 172.29.130.0/17 next-hop 172.30.25.1;
route 172.29.13.0/24 {
next-hop 172.30.25.1;
no-readvertise;
}
route 172.29.16.0/12 next-hop 172.30.25.1;
route 172.29.20.0/24 next-hop 172.30.25.1;
}
[edit protocols ospf]
user@R1# show
export Export_OSPF;
area 0.0.0.0 {
interface ge-0/0/2.0;
interface ge-0/0/3.0;
interface lo0.0;
}
[edit policy-options]
user@R1# show
policy-statement Export_OSPF {
term match-static-routes {
from {
protocol static;
route-filter 172.29.0.0/16 orlonger;
}
then accept;
}
}
-- Exhibit --
Referring to the exhibit, there is an OSPF policy to redistribute static routes.
Which routes will be propagated to OSPF neighbors?
A. 172.29.13.0/24 172.29.20.0/24
B. 172.29.130.0/17 172.29.13.0/24 172.20.16.0/12
C. 172.29.130.0/17 172.29.20.0/24
D. 172.29.130.0/17 172.29.13.0/24
Answer: C

NEW QUESTION: 4
A customer is considering migrating their existing non-EMC storage arrays to an XtremIO array. The current environment consists of 350 servers running VMware ESXi 5.5 with 5000 virtual machines. The customer has various tools in place to monitor performance and collect statistics. On average, their service time is 32 ms and utilization is at 75%. In the past, the customer has had performance issues.
Based on Little's Law, what is the calculated response time on the existing environment?
A. 192 ms
B. 256 ms
C. 128 ms
D. 332 ms
Answer: C
Explanation:
Explanation/Reference:
Disk service time T(s) = 32 ms (service time for one I/O).
Response time T(r) is calculated as: T(s) / (1 - Utilization), which here calculates to 32 ms/ (1-0.75) = 128 ms.
References: https://community.emc.com/thread/145100?tstart=0

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