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NEW QUESTION: 1
Which of the following is a public IP address?
A. 68.24.78.221
B. 10.156.89.1
C. 172.16.152.48
D. 192.168.25.101
Answer: A
Explanation:
Explanation/Reference:
Incorrect:
The private address space specified in RFC 1918 is defined by the following three address blocks:
not D: 192.168.0.0/16
The 192.168.0.0/16 private network can be interpreted either as a block of 256 class C network IDs or as a
16-bit assignable address space (16 host bits) that can be used for any subnetting scheme within the private organization. The 192.168.0.0/16 private network allows the following range of valid IP addresses:
192.168.0.1 to 192.168.255.254.
Not A:
10.0.0.0/8
The 10.0.0.0/8 private network is a class A network ID that allows the following range of valid IP addresses: 10.0.0.1 to 10.255.255.254. The 10.0.0.0/8 private network has 24 host bits that can be used for any subnetting scheme within the private organization.
Not C:
172.16.0.0/12
The 172.16.0.0/12 private network can be interpreted either as a block of 16 class B network IDs or as a
20-bit assignable address space (20 host bits) that can be used for any subnetting scheme within the private organization. The 172.16.0.0/12 private network allows the following range of valid IP addresses:
172.16.0.1 to 172.31.255.254.
Reference: Technet, Public and Private Addresses

NEW QUESTION: 2
Refer to the exhibit.

Which action must be taken before the maintenance policy can be committed?
A. Set the policy to apply the change on the next reboot.
B. Specify a maintenance time by selecting a schedule.
C. Associate a service profile to the maintenance policy.
D. Set the soft shutdown timer to a specific time.
Answer: B

NEW QUESTION: 3
展示を参照してください。

管理者は、10.0.0.0 / 30サブネットのアドレス最後に使用可能なアドレスで設定されたポートでCiscoDiscoveryProtocolをオフにする必要があります。どのコマンドセットが要件を満たしていますか？
A. interface gi0/0
no cdp advertise-v2
B. interface gi0/1
no cdp enable
C. interface gi0/0
no cdp run
D. interface gi0/1
clear cdp table
Answer: C

NEW QUESTION: 4
What happens when you attempt to compile and run the following code?
#include <vector>
#include <iostream>
#include <algorithm>
#include <functional>
using namespace std;
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out<<val<<" "; } };
struct Add : public binary_function<int, int, int> {
int operator() (const int & a, const int & b) const {
return a+b;
}
};
int main() {
int t[]={1,2,3,4,5,6,7,8,9,10};
vector<int> v1(t, t+10);
vector<int> v2(10);
transform(v1.begin(), v1.end(), v2.begin(), bind1st(Add(), 1));
for_each(v2.rbegin(), v2.rend(), Out<int>(cout));cout<<endl;
return 0;
}
Program outputs:
A. compilation error
B. 11 10 9 8 7 6 5 4 3 2
C. 2 3 4 5 6 7 8 9 10 11
D. 1 2 3 4 5 6 7 8 9 10
E. 10 9 8 7 6 5 4 3 2 1
Answer: B