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NEW QUESTION: 1
Given:
import java.util.*;
public class SearchText {
public static void main(String[] args) {
Object[] array1 = new Object[3];
array1[0] = "foo"; array1[0] = 1;
array1[0] = 'a';
int index = Arrays.binarySearch(array1, "bar");
System.out.println(index);
}
}
What is the result?
A. - 1
B. 0
C. Compilation fails
D. 1
E. An exception is thrown at runtime
Answer: E
Explanation:
The code compiles fine.
An exception is thrown at runtime due to data type comparison mismatch:
Exception in thread "main" java.lang.ClassCastException: java.lang.String cannot be cast to
java.lang.Integer
at java.lang.Integer.compareTo(Integer.java:52)
at java.util.Arrays.binarySearch0(Arrays.java:1481)
at java.util.Arrays.binarySearch(Arrays.java:1423)
at searchtext.SearchText.main(SearchText.java:22)
Note:binarySearch
public static int binarySearch(char[] a,
char key)
Searches the specified array of chars for the specified value using the binary search algorithm.
The array must be sorted (as by the sort method, above) prior to making this call. If it is not sorted,
the results are undefined. If the array contains multiple elements with the specified value, there is
no guarantee which one will be found.
Parameters:
a - the array to be searched.
key - the value to be searched for.
Returns:
index of the search key, if it is contained in the list; otherwise, (-(insertion point) - 1). The insertion
point is defined as the point at which the key would be inserted into the list: the index of the first element greater than the key, or list.size(), if all elements in the list are less than the specified key. Note that this guarantees that the return value will be >= 0 if and only if the key is found.

NEW QUESTION: 2
次の図に示すように、WEBPROD-AS-USE2という名前のAzure可用性セットを含むAzureサブスクリプションがあります。


14台の仮想マシンをWEBPROD-AS-USE2に追加します。
ドロップダウンメニューを使用して、図に示されている情報に基づいて各ステートメントを完了する回答を選択します。
注：それぞれの正しい選択は1ポイントの価値があります。

Answer:
Explanation:

NEW QUESTION: 3
You have a four-node cluster with instances RDBD1, RDBD2, RDBD3, and RDBD4. While evaluating statspack reports, you find nq: TX- index contention on page one under the category op 5 Timed Events.
Further study finds an unusually high number of c buffer busy waits in the Wait Events section.
Checking the Instance Activity Stats section, you see an unusually high value for eaf Node Splits.
Using v$segment_statistics, you identify that the top segment with c buffer busy waits is the index products_pk, which obtains the primary key from a sequence. You wish to present alternative solutions to the team to help reduce contention.
Which three actions would you recommend to reduce the overheads? (Choose three.)
A. Re-create the table using a natural key instead of a surrogate key.
B. Encourage shorter transactions.
C. Set fast_start_mttr_target to a higher value.
D. Increase the sequence cache size if retaining the sequence.
E. Set _lm_msg_batch_size to a higher value.
F. Re-create the index as a global hash partitioned index.
Answer: A,D,F