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NEW QUESTION: 1
Was passiert, wenn Sie in SAP Materials Management einen bewerteten Wareneingang für eine Bestellposition mit Materialstammsatz und Kontierung K (Kostenstelle) buchen? Bitte wählen Sie die richtige Antwort.
A. Der Materialbeleg wird ohne Buchhaltungsbeleg erstellt.
B. Das System erhöht den Materialbestand
C. Das System belastet das in der Bestellung angegebene Verbrauchskonto
D. Der gleitende Durchschnittspreis des Materials wird aktualisiert
Answer: C

NEW QUESTION: 2
What determines whether a loop continues execution?
A. guards
B. partitions
C. test nodes
D. behaviors
E. clauses
Answer: C

NEW QUESTION: 3
Azureイベントハブからクリックストリームデータを受信するAzure Stream Analyticsジョブがあります。
Stream Analyticsジョブでクエリを定義する必要があります。クエリは次の要件を満たしている必要があります。
*訪問者の国に基づいて、各10秒ウィンドウ内のクリック数をカウントします。
* 1回のクリックが複数回カウントされないようにしてください。
クエリをどのように定義する必要がありますか？
A. SELECT Country, Avg(*) AS Average
FROM ClickStream TIMESTAMP BY CreatedAt
GROUP BY Country, HoppingWindow(second, 10, 2)
B. SELECT Country, Count(*) AS Count
FROM ClickStream TIMESTAMP BY CreatedAt
GROUP BY Country, TumblingWindow(second, 10)
C. SELECT Country, Count(*) AS Count
FROM ClickStream TIMESTAMP BY CreatedAt
GROUP BY Country, SessionWindow(second, 5, 10)
D. SELECT Country, Avg(*) AS Average
FROM ClickStream TIMESTAMP BY CreatedAt
GROUP BY Country, SlidingWindow(second, 10)
Answer: B
Explanation:
Explanation
Tumbling window functions are used to segment a data stream into distinct time segments and perform a function against them, such as the example below. The key differentiators of a Tumbling window are that they repeat, do not overlap, and an event cannot belong to more than one tumbling window.
Example:
Reference:
https://docs.microsoft.com/en-us/azure/stream-analytics/stream-analytics-window-functions

NEW QUESTION: 4
Refer to the exhibit.

The company uses EIGRP as the routing protocol. What path will packets take from a host on the 192.168.10.192/26 network to a host on the LAN attached to router R1?
A. The path of the packets will be R3 to R2 to R1.
B. The path of the packets will be both R3 to R2 to R1 AND R3 to R1.
C. The path of the packets will be R3 to R1 to R2.
D. The path of the packets will be R3 to R1.
Answer: D
Explanation:
Host on the LAN attached to router R1 belongs to 192.168.10.64/26 subnet. From the output of the routing table of R3 we learn this network can be reach via 192.168.10.9, which is an IP address in 192.168.10.8/30 network (the network between R1 & R3) -> packets destined for 192.168.10.64 will be routed from R3 -> R1 -> LAN on R1.