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NEW QUESTION: 1
낮은 습도 수준 직원이 배치 된 데이터 센터에서는
A. 전기 절연이 마르게 됨
B. 에어컨 성능 저하
C. 정전기 축적에 추가
D. 의료 책임 요인을 증가시킵니다.
Answer: C

NEW QUESTION: 2
A service provider is deploying L2VPN LAN services in its MPLS cloud. Which statement is true regarding LDP signaling and autodiscovery?
A. LDP signaling requires that each P is identified, and that a targeted LDP session is active for auto discovery to take place.
B. LDP signaling requires that each PE is identified, and that a targeted LDP session is active for auto discovery to take place.
C. LDP signaling requires that each PE is identified, and that an LDP session is active with its P neighbor for autodiscovery to take place.
D. LDP signaling requires that each PE is identified, and that a targeted LDP session with a BGP route reflector is active for autodiscovery to take place.
Answer: B

NEW QUESTION: 3
In Azure Active Directory (AD) Privileged Identify Management konfigurieren Sie die Rolleneinstellungen für die Eigentümerrolle eines Azure-Abonnements wie in der folgenden Abbildung gezeigt.

In Azure AD Privileged Identify Management weisen Sie einem Benutzer mit dem Namen Benutzer1 die Eigentümerrolle für das Abonnement zu und setzen den Zuweisungstyp auf Dauerberechtigt.
Verwenden Sie die Dropdown-Menüs, um die Antwortauswahl auszuwählen, die jede Anweisung basierend auf den in der Grafik dargestellten Informationen vervollständigt.
HINWEIS: Jede richtige Auswahl ist einen Punkt wert.

Answer:
Explanation:

Explanation

NEW QUESTION: 4
View the exhibit and examine the structure of the EMPLOYEES table.

You want to select all employees having 100 as their MANAGER_ID manages and their manager.
You want the output in two columns: the first column should have the employee's manager's LAST_NAME and the second column should have the employee's LAST_NAME.
Which SQL statement would you execute?
A. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON m.employee_id = e.manager_idWHERE e.manager_id=100;
B. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON e.employee_id = m.manager_idWHERE m.manager_id=100;
C. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eWHERE m.employee_id = e.manager_id AND e.manager_id=100
D. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON m.employee_id = e.manager_idWHERE m.manager_id=100;
Answer: A