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NEW QUESTION: 1
Sie haben eine nicht partitionierte Tabelle mit einer einzelnen Dimension. Der Tisch heißt dim. Produkte.Projektionen.
Die Tabelle wird häufig von mehreren Branchenanwendungen abgefragt. Die Daten werden im Laufe des Tages häufig durch zwei Prozesse aktualisiert.
Benutzer berichten, dass die Antworten langsamer als erwartet sind, wenn sie Daten von dim.Products.Projections abfragen.
Das Problem tritt auf, wenn eine große Anzahl von Zeilen aktualisiert wird.
Sie müssen verhindern, dass die Aktualisierungen die Abfragen verlangsamen.
Was tun?
A. Führen Sie die Anweisung dbcc updateusage aus.
B. Setzen Sie SET ALLOW_SNAPSHOT_ISOLATION auf ON.
C. Verwenden Sie einen Tabellenwert-Parameter.
D. Verwenden Sie die Option nolock.
E. Verwenden Sie die Option max worker threads.
Answer: A

NEW QUESTION: 2
Which of the following information do you check to directly identify a fault in the firewall if the data transmission is interrupted?
A. Session table
B. Global statistics about the firewall
C. Log
D. Alarms
Answer: A

NEW QUESTION: 3
회사의 웹 애플리케이션이 Application Load Balancer 뒤의 Amazon EC2 인스턴스에서 실행 중입니다. 이 회사는 최근 정책을 변경했으며 이제 특정 국가에서만 응용 프로그램에 액세스 해야 합니다.
이 요구 사항을 충족하는 구성은 무엇입니까?
A. EC2 인스턴스가 포함 된 서브넷에 대한 네트워크 ACL을 구성하십시오.
B. VPC의 Application Load Balancer에서 AWS WAF를 구성하십시오.
C. Application Load Balancer에서 보안 그룹을 구성하십시오.
D. EC2 인스턴스의 보안 그룹을 구성하십시오.
Answer: B
Explanation:
Explanation
https://aws.amazon.com/es/blogs/security/how-to-use-aws-waf-to-filter-incoming-traffic-from-embargoed-count

NEW QUESTION: 4



A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
COUNT(OrderAmount) AS OrderAmount
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
ORDER BY OrderAmount DESC
B. SELECT CustomerID, CustomerName, ShippingCountry
FROM
(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry,
RANK() OVER (PARTITION BY c.CustomerID
ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName,
o.ShippingCountry) cs
WHERE Rnk = 1
C. SELECT CustomerID, CustomerName, ShippingCountry
FROM
(SELECT c.CustomerID, c.CustomerName,
o. ShippingCountry,
RANK() OVER (PARTITION BY c. CustomerID
ORDER BY o. OrderAmount DESC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName,
o.ShippingCountry) cs
WHERE Rnk = 1
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(OrderAmount) DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
Where o.Rnk = 1
Answer: C