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NEW QUESTION: 1
Refer to the exhibit. The network is converged.After link-state advertisements are received from Router_A, what information will Router_E contain in its routing table for the subnets
208.149.23.64 and 208.149.23.96?

A. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, Serial1/0 208.149.23.96[110/13] via 190.173.23.10,
00:00:16, Serial1/0 208.149.23.96[110/13] via 190.173.23.10, 00:00:16, FastEthemet0/0
B. 208.149.23.64[110/3] via 190.172.23.10, 00:00:07, Serial1/0 208.149.23.96[110/3] via 190.173.23.10,
00:00:16, Serial1/0
C. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, FastEthemet0/0 208.149.23.96[110/13] via
190.173.23.10, 00:00:16, FastEthemet0/0
D. 208.149.23.64[110/1] via 190.172.23.10, 00:00:07, Serial1/0 208.149.23.96[110/3] via 190.173.23.10,
00:00:16, FastEthemet0/0
Answer: C
Explanation:
Router_E learns two subnets subnets 208.149.23.64 and 208.149.23.96 via Router_A through FastEthernet interface. The interface cost is calculated with the formula 108 / Bandwidth. For FastEthernet it is 108 / 100 Mbps = 108 / 100,000,000 = 1.
Therefore the cost is 12 (learned from Router_A) + 1 = 13 for both subnets -> The cost through T1 link is much higher than through T3 link (T1 cost = 108 / 1.544 Mbps = 64; T3 cost = 108 / 45 Mbps = 2) so surely OSPF will choose the path through T3 link -> Router_E will choose the path from Router_A through FastEthernet0/0, not Serial1/0.
In fact, we can quickly eliminate answers B, C and D because they contain at least one subnet learned from Serial1/0 -> they are surely incorrect.

NEW QUESTION: 2
次のうち、最も起こりそうなものはどれですか？

A. 潜在的なハッカーは、どのアーキテクチャが使用されているかを判断するためにバナーをつかむ可能性があります
B. ハッカーがWebサーバーインターフェイスを使用してピボットを試みました。
C. DNSがサーバーのIPアドレスに対して正しく構成されていません。
D. サーバーでDoSが発生しており、リクエストがタイムアウトしています。
Answer: B

NEW QUESTION: 3
The primary purpose for using one-way encryption of user passwords within a system is which of the following?
A. It minimizes the amount of storage required for user passwords
B. It prevents an unauthorized person from reading or modifying the password list
C. It minimizes the amount of processing time used for encrypting password
D. It prevents an unauthorized person from trying multiple passwords in one logon attempt
Answer: B