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NEW QUESTION: 1
Refer to the exhibit.
An engineer is troubleshooting a control connection Issue. What does "connect" mean in this how control connections output?
A. Control connection is connected
B. Control connection is up
C. Control connection attempt is in progress
D. Control connection is down
Answer: C
NEW QUESTION: 2
Refer to the exhibit.
Which ntatement in true about the downward bit?
A. It informn the PE router that the LSA metric han been recently decreaned to 1 and that partial SPF calculation cannot
be delayed.
B. It forcen the CE router to une a backup link inntead of nending traffic via MPLS VPN.
C. It informn the PE router that the LSA wan already redintributed into BGP by another PE router and that the LSA munt
not be redintributed into BGP again.
D. It forcen the CE router to inntall the LSA with the downward bit net into itn routing table an a dincard route.
Answer: C
Explanation:
From RFC 4577, npecifically nection 4.2.5.1
When a type 3 LSA in nent from a PE router to a CE router, the DN bit [OSPF-DN] in the LSA Optionn field MUST be net.
Thin in uned to ennure that if any CE router nendn thin type 3 LSA to a PE router, the PE router will not redintribute it
further.
When a PE router needn to dintribute to a CE router a route that comen from a nite outnide the latter'n OSPF domain,
the PE router prenentn itnelf an an ASBR (Autonomoun Syntem Border Router), and dintributen the route in a type 5
LSA. The DN bit [OSPF-DN] MUST be net in thene LSAn to ennure that they will be ignored by any other PE routern that
receive them.
NEW QUESTION: 3
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply only to that question.
You need to deploy a new Microsoft SQL Server environment that meets the following requirements:
* The SQL Server instance must be highly available.
* There must be minimal downtime incurred during hardware failure or operating system maintenance.
* All instance-level security settings and SQL Server Agent jobs must be available without additional synchronization tasks.
What should you implement?
A. a Windows cluster with a shared-nothing architecture
B. a file share witness
C. a Microsoft SQL Server failover cluster instance (FCI)
D. an Always On Availability Group with secondary replicas in asynchronous-commit mode
E. a Microsoft Azure Stretch Database
F. log shipping
G. an Always On Availability Group with all replicas in synchronous-commit mode
Answer: C
Explanation:
Explanation
As part of the SQL Server Always On offering, Always On Failover Cluster Instances leverages Windows Server Failover Clustering (WSFC) functionality to provide local high availability through redundancy at the server-instance level-a failover cluster instance (FCI). An FCI is a single instance of SQL Server that is installed across Windows Server Failover Clustering (WSFC) nodes and, possibly, across multiple subnets.
When there is hardware or software failure of a server, the applications or clients connecting to the server will experience downtime. When a SQL Server instance is configured to be an FCI (instead of a standalone instance), the high availability of that SQL Server instance is protected by the presence of redundant nodes in the FCI.
References:
https://docs.microsoft.com/en-us/sql/sql-server/failover-clusters/windows/always-on-failover-cluster-instances-sq
NEW QUESTION: 4
Given the following code fragment:
public class Calc {
public static void main (String [] args) {
//* insert code here Line ** System.out.print("The decimal value is" + var);
}
}
Which three code fragments, when inserted independently at line **, enable the code to compile/
A. int var = 0b_1001;
B. long var = 0b100_01L;
C. double var = 0b10_01D;
D. double var = 0b10_01;
E. float var = 0b10_01F;
F. float var = 0b10_01;
Answer: B,D,F
Explanation:
B: output 17
C: output 9.0
E: output 9.0
Not A: A _ character cannot begin a number.
Not D: A float cannot be defined as a binary number (with literal B)
Not F: A float cannot be defined as a decimal number (with literal D)
Note1:
In Java SE 7 and later, any number of underscore characters (_) can appear anywhere between
digits in a numerical literal. This feature enables you, for example. to separate groups of digits in
numeric literals, which can improve the readability of your code.
For instance, if your code contains numbers with many digits, you can use an underscore
character to separate digits in groups of three, similar to how you would use a punctuation mark
like a comma, or a space, as a separator.
You can place underscores only between digits; you cannot place underscores in the following
places:
*At the beginning or end of a number (not A)
*Adjacent to a decimal point in a floating point literal
*Prior to an F or L suffix
*In positions where a string of digits is expected
Note 2:An integer literal is of type long if it ends with the letter L or l; otherwise it is of type int. It is recommended that you use the upper case letter L because the lower case letter l is hard to distinguish from the digit 1.
Values of the integral types byte, short, int, and long can be created from int literals. Values of type long that exceed the range of int can be created from long literals. Integer literals can be expressed by these number systems:
Decimal: Base 10, whose digits consists of the numbers 0 through 9; this is the number system you use every day Hexadecimal: Base 16, whose digits consist of the numbers 0 through 9 and the letters A through F Binary: Base 2, whose digits consists of the numbers 0 and 1 (you can create binary literals in Java SE 7 and later)
Reference: The Java Tutorials,Primitive Data Types: Using Underscore Characters in Numeric Literals Integer Literals
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