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NEW QUESTION: 1
DRAG DROP
Drag and drop the route source codes in a routing table from the left onto the correct meanings on the right.

Answer:
Explanation:

NEW QUESTION: 2
The department entity has a unidirectional OneToMany relationship to the employee entity. The developer wants to model this relationship as a java.util.map such that the key of map is true employee name. The primary key of the Employees entity is empId, an integer.
Which of the following is correct?
A. @OneToMany @mapKey (name = "name") map < integer, Employee> Employees;
B. @OneToMany (targetEntity = Employee.class)
@MapKeyClass (string.class)
map employees;
C. @OneToMany @mapsId (name = "name") map <String, Employee> employees;
D. @OneToMany @MapKeyJoinColumn (name = "name") map <String, Employee> employees;
Answer: A
Explanation:
Explanation/Reference:
Annotation Type MapKey specifies the map key for associations of type java.util.Map when the map key is itself the primary key or a persistent field or property of the entity that is the value of the map.
Example:
@ Entity
public class Department {
. ..
@ OneToMany(mappedBy="department")
@ MapKey(name="name")
public Map<String, Employee> getEmployees() {... }
. ..
}
@Entity
public class Employee {
@ Id public Integer getEmpId() { ... }
. ..
@ ManyToOne
@ JoinColumn(name="dept_id")
public Department getDepartment() { ... }
...
}
Reference: javax.persistence, Annotation Type MapKey

NEW QUESTION: 3
The IP address for the trusted interface on your Firebox is 10.0.40.1/24, but you want to change the IP address for this interface. How can you avoid a network outage for clients on the trusted network when you change the interface IP address to 10.0.50.1/24? (Select one.)
A. Add IP addresses on the 10.0.40.0/24 subnet to the DHCP Server IP address pool for this interface.
B. Create a 1-to-1 NAT rule for traffic from the 10.0.40.0/24 subnet to addresses on the 10.0.50.0/24 subnet.
C. Add 10.0.40.1/24 as a secondary IP address for the interface.
D. Add a route to 10.0.40.0/24 with the gateway 10.0.50.1.
Answer: C