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NEW QUESTION: 1
Note: This question is part of a series of questions that present the same scenario.
Each questions in the series contains a unique solution that might meet the stated goals.
Some questions sets might have more than one correct solution, while others might not have a correct solution.
After you answer a question in this section, you will NOT be able to return to it.
As a result, these questions will not appear in the review scree.
You create an Ubuntu Linux virtual machine (VM) by using the Azure Portal.
You do not specify a password when you create the VM.
You need to connect to the terminal of the VM.
Solution: You use the Connect button on the Overview blade for the VM.
Does the solution meet the goal?
A. No
B. Yes
Answer: A
Explanation:
https://docs.microsoft.com/en-us/azure/virtual-machines/virtual-machines-linux-quick-create-portal?toc=%2fazure%2fvirtual-machines%2flinux%2ftoc.json

NEW QUESTION: 2
価値の高いオンライン金融取引システムの銀行にとって、次の特徴のうちどれが重要ですか？
A. 機密性
B. 認証
C. 識別
D. 監査監視
Answer: A

NEW QUESTION: 3
HOTSPOT







Answer:
Explanation:

Explanation:
An IPv4 address consists of 32 bits. The first x number of bits in the address is the network address and the remaining bits are used for the host addresses. The subnet mask defines howmany bits form the network address and from that, we can calculate how many bits are used for the host addresses.
The formula to calculate the number of hosts in a subnet is 2n - 2. The "n" in the host's formula represents the number of bits used for host addressing.If we apply the formula
(22 - 2), we can determine that the following subnets should be configured:
Sales network - /26 - This will provide up to 62 usable IP addresses (64-2 for subnet and broadcast IP)
HR network - /27 - This will provide for up to 30usable IP's (32-2)
IT - /28 - This will provide for up to 14 usable IP's (16-2)
Finance - /26 - Note that a /27 is 32 IP addresses but 2 of those are reserved for the network and broadcast IP's and can't be used for hosts.
Marketing - /28
If we add up howmany IP blocks are used that is 64+32+16+64+16=192.
A /24 contains 256 IP addresses, so 256-192=64.
So the last unused box should be a /26, which equates to 64 addresses