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NEW QUESTION: 1
A user has launched an EC2 instance from an instance store backed AMI. The infrastructure team wants
to create an AMI from the running instance. Which of the below mentioned credentials is not required
while creating the AMI?
A. AWS account ID
B. Access key and secret access key
C. X.509 certificate and private key
D. AWS login ID to login to the console
Answer: D
Explanation:
When the user has launched an EC2 instance from an instance store backed AMI and the admin team
wants to create an AMI from it, the user needs to setup the AWS AMI or the API tools first. Once the tool is
setup the user will need the following credentials:
AWS account ID;
AWS access and secret access key;
X.509 certificate with private key.
Reference: http://docs.aws.amazon.com/AWSEC2/latest/UserGuide/creating-an-ami-instance-store.html

NEW QUESTION: 2
Which of the following audit steps would be most effective to review proper recording of and accountability over physical assets?
I.Physically inspect all assets on the organization's property.
II.
Select a sample department and physically inspect assets in the department.
III.
Select a sample from the organization's records of physical assets and physically locate each asset.
IV.
Identify assets at a sample of locations and trace to the organization's records.
A. III and IV only.
B. I and IV only.
C. I only.
D. II and III only.
Answer: A

NEW QUESTION: 3



A. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
B. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo L.CustNo
C. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
D. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
E. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
F. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
G. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo L.CustNoWHERE D.CustNo IS NULL
H. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
Answer: C
Explanation:
The SQL INTERSECT operator is used to return the results of 2 or more SELECT statements. However, it only returns the rows selected by all queries or data sets. If a record exists in one query and not in the other, it will be omitted from the INTERSECT results.
References: https://www.techonthenet.com/sql/intersect.php

NEW QUESTION: 4

A. Amazon DynamoDB
B. Amazon EFS
C. Amazon EBS
D. Amazon S3
Answer: B