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NEW QUESTION: 1
Which two mechanisms can be used to eliminate Cisco Express Forwarding polarization? (Choose two.)
A. alternating cost links
B. Cisco Express Forwarding antipolarization
C. different hashing inputs at each layer of the network
D. the unique-ID/universal-ID algorithm
Answer: C,D
Explanation:
This document describes how Cisco Express Forwarding (CEF) polarization can cause suboptimal use of redundant paths to a destination network. CEF polarization is the effect when a hash algorithm chooses a particular path and the redundant paths remain completely unused.
How to Avoid CEF Polarization
- Alternate between default (SIP and DIP) and full (SIP + DIP + Layer4 ports) hashing inputs configuration at each layer of the network.
- Alternate between an even and odd number of ECMP links at each layer of the network.The CEF load-balancing does not depend on how the protocol routes are inserted in the routing table. Therefore, the OSPF routes exhibit the same behavior as EIGRP. In a hierarchical network where there are several routers that perform load-sharing in a row, they all use same algorithm to load-share.
The hash algorithm load-balances this way by default:
1: 1
2: 7-8
3: 1-1-1
4: 1-1-1-2
5: 1-1-1-1-1
6: 1-2-2-2-2-2
7: 1-1-1-1-1-1-1
8: 1-1-1-2-2-2-2-2
The number before the colon represents the number of equal-cost paths. The number after the colon represents the proportion of traffic which is forwarded per path.
This means that:
- For two equal cost paths, load-sharing is 46.666%-53.333%, not 50%-50%. - For three equal cost paths, load-sharing is 33.33%-33.33%-33.33% (as expected). - For four equal cost paths, load-sharing is 20%-20%-20%-40% and not 25%-25%
25%-25%.
This illustrates that, when there is even number of ECMP links, the traffic is not load-
balanced. - Cisco IOS introduced a concept called unique-ID/universal-ID which helps avoid CEF polarization. This algorithm, called the universal algorithm (the default in current Cisco IOS versions), adds a 32-bit router-specific value to the hash function (called the universal ID - this is a randomly generated value at the time of the switch boot up that can can be manually controlled). This seeds the hash function on each router with a unique ID, which ensures that the same source/destination pair hash into a different value on different routers along the path. This process provides a better network-wide load-sharing and circumvents the polarization issue. This unique -ID concept does not work for an even number of equal-cost paths due to a hardware limitation, but it works perfectly for an odd number of equal-cost paths. In order to overcome this problem, Cisco IOS adds one link to the hardware adjacency table when there is an even number of equal-cost paths in order to make the system believe that there is an odd number of equal-cost links.
Reference: http://www.cisco.com/c/en/us/support/docs/ip/express-forwarding-cef/116376technote-cef-00.html

NEW QUESTION: 2
The following SAS program is submitted:

If the value for the variable Jobcode is: PILOT2, what is the value of the variable Description?
A. Senior Pilot
B. SENIOR PILOT
C. Unknown
D. ' ' (missing character value)
Answer: C

NEW QUESTION: 3
Which service is started at boot time, instead of on demand?
A. sprayd
B. ping
C. telnet
D. walld
E. mountd
F. rpcbind
Answer: E

NEW QUESTION: 4
The Data Encryption Algorithm performs how many rounds of substitution and permutation?
A. 0
B. 54 D. 64
C. 1
Answer: A
Explanation:
Source: TIPTON, Hal, (ISC)2, Introduction to the CISSP Exam presentation.